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Thursday, July 16, 2009

ONE EQUALS ZERO

Consider the following integral:
INTEGRAL (1/x) dx
Perform integration by parts:
let u = 1/x , dv = dx du = -1/x2 dx , v = x
Then obtain:
INTEGRAL (1/x) dx = (1/x)*x - INTEGRAL x (-1/x2) dx
= 1 + INTEGRAL (1/x) dx
which implies that 0 = 1.

3 comments:

  1. hi, missed to insert the constant of integration! That will riddle out this.

    ReplyDelete
  2. yes Jitender, thats the fact behind this . This is to show the importance of the constant of integration.

    ReplyDelete
  3. ya the constant...
    Similarly see this 1..
    integral x+1 dx
    =sq of(x+1)/2
    and also sq of (x)/2 + x...

    ReplyDelete

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