Consider the following integral:
INTEGRAL (1/x) dx
Perform integration by parts:
let u = 1/x , dv = dx du = -1/x2 dx , v = x
Then obtain:
INTEGRAL (1/x) dx = (1/x)*x - INTEGRAL x (-1/x2) dx
= 1 + INTEGRAL (1/x) dx
which implies that 0 = 1.
Thursday, July 16, 2009
Subscribe to:
Post Comments (Atom)
Posts
hi, missed to insert the constant of integration! That will riddle out this.
ReplyDeleteyes Jitender, thats the fact behind this . This is to show the importance of the constant of integration.
ReplyDeleteya the constant...
ReplyDeleteSimilarly see this 1..
integral x+1 dx
=sq of(x+1)/2
and also sq of (x)/2 + x...